Here’s a brain teaser !.
Can you “build” all the whole numbers between 1 and 100 using only
four 4’s ?
4
and symbol ..
+ - x / ( ) . x^2 =
oh.. and also factorial..
!
i can get the number 9 as 4+4 + 4/4 ,
hehe.
post your calculated in comment.. let’s see if can get up to 100.
Source : Great-International-Math-Keys-Book
p/s : it is from 1970’s ~
to get 10
10 is 4 + 4 + (4/4) + (4/4)
hehehe..
Eleven is
11 = 4 + 4 + 4 – (4/4)
both above invalid. as there is a rules..
4 cannot be used more than 4 times..
(44/4) – (4/4) also cannot..
revising..
10 = (4 – (4/4))! + 4
Must solve in sequence? Here is some easy ones …
16 = 4+4+4+4
20 = (4!-4)*4/4
24 = 44-4!+4
28 = 44-4*4
32 = (4^2)
36 = 44-4-4
40 = 4!+4!-4-4
43 = 44-4/4
44 = 44*4/4
45 = 44+4/4
48 = (4+4+4)*4
52 = 44+4+4
56 = 4!+4!+4+4
60 = 44+4*4
64 = 4^2+4^2+4^2+4^2
68 = 4*4+4*4
88 = 44+44
96 = (4!*4)*4/4
95 = (4!*4)-4/4
97 = (4!*4)+4/4
eleven..
11 = 4^2 – (4/4) – 4
12 = 4^2 – 4 * 4/4
13 = 4^2 – 4 + (4/4)
14 = 4^2-(4+4)/4
18 = 4^2+(4+4)/4
15 = 4*4-(4/4)
17 = 4*4+(4/4)
27 = (44/4) + 4^2
19 = 4^2 + 4 – (4/4)
21 = 4^2 + 4 + (4/4)
22 = 4! – (4+4)/4
26 = 4! + (4+4)/4
49 = 4! + 4! + 4/4
47 = 4! + 4! – 4/4
54 = 4! + 4! + 4! /4
72 = 4^2 * 4 + 4 + 4
76 = 4!+4!+4!+4
80 = 4^2 + 4! + 4! + 4^2
23 = 4! – ((4^2) /(4*4))
25 = 4! + ((4^2) /(4*4))
29 = 4! + 4+ (4/4)
[4!+(4/4)]*4
so easy i break this puzzle in10sec
hope you see because i’m new